JEE Main 2019PhysicsCurrent ElectricityPotentiometereasyMCQ

JEE Main 2019Current Electricity Question with Solution

From: JEE Main 2019 (Online) 8th April Evening Slot

Question

In the circuit shown, a four-wire potentiometer is made of a 400 cm long wire, which extends between A and B. The resistance per unit length of the potentiometer wire is r = 0.01 /cm. If an ideal voltmeter is connected as shown with jockey J at 50 cm from end A, the expected reading of the voltmeter will be :- JEE Main 2019 (Online) 8th April Evening Slot Physics - Current Electricity Question 257 English

This question includes a diagram. The text above accompanies the figure.

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Show full solutionCorrect option: A
Correct answer
A0.25 V

Step-by-step explanation

Resistance of wire AB = 400 × 0.01 = 4

i =

Now voltmeter reading = i (Resistance of 50 cm length)
= (0.5 A) (0.01 × 50) = 0.25 volt

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About this question

This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.