JEE Main 2019PhysicsCurrent ElectricityGalvanometer Voltmeter And AmmetermediumMCQ
JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
A galvanometer of resistance 100 Ω has 50 divisions on its scale and has sensitivitv of 20 μA/division. It is
to be converted to a voltmeter with three ranges of 0-2V, 0-10 V and 0-20 V. The appropriate circuit to do so
is
Choose an option
▸Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
20 × 50 × 10–6 = 10–3 Amp
V1=10−32=100+R1
1900=R1
V2=10−310=(2000+R2)
R2=8000
V3=10−320=10×103+R3=10×103R3
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