JEE Main 2019 — Current Electricity Question with Solution
From: JEE Main 2019 (Online) 12th April Evening Slot
Question
A moving coil galvanometer, having a resistance G, produces full scale deflection when a current Ig flows
through it. This galvanometer can be converted into (i) an ammeter of range 0 to I0(I0 > Ig) by connecting a
shunt resistance RA to it and (ii) into a voltmeter of range 0 to V (V = GI0) by connecting a series resistance
RV to it. Then,
Choose an option
Show full solutionCorrect option: D
Correct answer
D and
Step-by-step explanation
Galvanometer is converted into ammeter of range 0 to I0 :
(Io - Ig)RA = IgG
............(1)
Galvanometer is converted into voltmeter of range 0 to V :
V = Ig(RV + G)
Also given, V = GI0
GI0 = Ig(RV + G)
.........(2)
From equation (1) and (2)
(Io - Ig)RA = IgG
............(1)
Galvanometer is converted into voltmeter of range 0 to V :
V = Ig(RV + G)
Also given, V = GI0
GI0 = Ig(RV + G)
.........(2)
From equation (1) and (2)
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This is a previous-year question from JEE Main 2019, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.