JEE Main 2018 — Current Electricity Question with Solution
From: JEE Main 2018 (Online) 16th April Morning Slot
Question
A heating element has a resistance of 100 at room temperature. When it is connected to a supply of 220 V, a steady current of 2 A passes in it and temperature is 500oC more than room temperature. what is the temperature coefficient of resistance of the heating element ?
Choose an option
Show full solutionCorrect option: D
Correct answer
D2 104 oC1
Step-by-step explanation
When temperature increased by 500oC then, nrw registance
Rt = = 110
We know,
Rt = R0 (1 + t)
110 = 100 (1 + 500)
= oC1
Rt = = 110
We know,
Rt = R0 (1 + t)
110 = 100 (1 + 500)
= oC1
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This is a previous-year question from JEE Main 2018, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.