JEE Main 2023 — Current Electricity Question with Solution
From: JEE Main 2023 (Online) 24th January Evening Shift
Question
A cell of emf 90 V is connected across series combination of two resistors each of 100 resistance. A voltmeter of resistance 400 is used to measure the potential difference across each resistor. The reading of the voltmeter will be :
Choose an option
Show full solutionCorrect option: A
Correct answer
A40 V
Step-by-step explanation
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This is a previous-year question from JEE Main 2023, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.