JEE Main 2021PhysicsCurrent ElectricityKirchhoffs Circuit LawsmediumNumerical
JEE Main 2021 — Current Electricity Question with Solution
From: JEE Main 2021 (Online) 25th July Evening Shift
Question
A 16 Ω wire is bend to form a square loop. A 9V supply having internal resistance of 1Ω is connected across one of its sides. The potential drop across the diagonals of the square loop is _______________ × 10−1 V
Enter your answer
▸Show full solutionCorrect answer: 45
Correct answer
45
Step-by-step explanation
Here assume current as
By KVL in outer loop
9 − 12i − 4i = 0
16i = 9
8i = 29 = 4.5
= 45 × 10-1
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Current Electricity chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
This is a previous-year question from JEE Main 2021, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.