JEE Main 2021 — Current Electricity Question with Solution
From: JEE Main 2021 (Online) 25th July Morning Shift
Question
In the given figure, there is a circuit of potentiometer of length AB = 10 m. The resistance per unit length is 0.1 per cm. Across AB, a battery of emf E and internal resistance 'r' is connected. The maximum value of emf measured by this potentiometer is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: A
Correct answer
A5 V
Step-by-step explanation
Max. voltage that can be measured by this potentiometer will be equal to potential drop across AB
RAB = 10 0.1 100 = 100 ohm.
V
RAB = 10 0.1 100 = 100 ohm.
V
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This is a previous-year question from JEE Main 2021, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.