JEE Main 2018 — Current Electricity Question with Solution
From: JEE Main 2018 (Online) 15th April Evening Slot
Question
Choose an option
Show full solutionCorrect option: D
Step-by-step explanation
Since rate of heat rate of heat , where ; here r is radius of wire and L is length of wire. Therefore,
.
Thus, rate of heat .
When length in halved and radius is doubled then, rate of heat
Therefore, rate of heat developed in wire will be increased 8 times.
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This is a previous-year question from JEE Main 2018, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.