JEE Main 2019 — Circular Motion Question with Solution
From: JEE Main 2019 (Online) 12th April Evening Slot
Question
A smooth wire of length 2r is bent into a circle and kept in a vertical plane. A bead can slide smoothly on
the wire. When the circle is rotating with angular speed about the vertical diameter AB, as shown in figure,
the bead is at rest with respect to the circular ring at position P as shown. Then the value of 2
is equal to -


This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
In ORP,
sin = = = sin 30o
= 30o
As the bead is at rest with respect to the circular ring at position P, The net force on bead is zero.
tan =
tan 30o =
=
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This is a previous-year question from JEE Main 2019, covering the Circular Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.