JEE Main 2013PhysicsCenter of Mass Momentum and CollisionMediumMCQ

JEE Main 2013 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2013 (07 Apr)

Question

This question has Statement - I and Statement - II  of the four choices given after the Statements, choose the one that best describes the two Statements.

Statement - I: A point particle of mass m moving with speed ν collides with stationary point particle of mass M. If the maximum energy loss possible is given as
f12mν2 then f=mM+m.

Statement - II: Maximum energy loss occurs when the particles get stuck together as a result of the collision.

Choose an option

Show full solutionCorrect option: B
Correct answer
BStatement- I is false, Statement- II is true.

Step-by-step explanation

Maximum energy loss will take place in perfectly inelastic collision, and is given by, ∆K=P22m-P22m+M
⇒∆K=P22m1-mm+M
⇒∆K=P22mMm+M
⇒∆K=12mv2Mm+M
On comparing with the given form of equation, we have, f=Mm+M

Hence Statement- I is false, Statement- II is true. ( As it is perfect Inelastic collision)

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About this question

This is a previous-year question from JEE Main 2013, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.