JEE Main 2023PhysicsCenter of Mass Momentum and CollisionEasyMCQ

JEE Main 2023 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2023 (31 Jan Shift 1)

Question

100 balls each of mass m moving with speed v simultaneously strike a wall normally and reflected back with same speed, in time t s. The total force exerted by the balls on the wall is

Choose an option

Show full solutionCorrect option: B
Correct answer
B200mvt

Step-by-step explanation

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Force exerted by each ball is F=∆p∆t, here, p is momentum and t is time.

So, for one ball F=mv-m-vt=2mvt

Now, total force exerted by the balls on the wall is Fnet=100×F=200mvt.

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About this question

This is a previous-year question from JEE Main 2023, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.