JEE Main 2023PhysicsCenter of Mass Momentum and CollisionEasyMCQ

JEE Main 2023 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2023 (13 Apr Shift 1)

Question

A bullet of 10 g leaves the barrel of gun with a velocity of 600 m s-1. If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be:

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Show full solutionCorrect option: A
Correct answer
A6 N s

Step-by-step explanation

The formula to calculate the impulse J on the gun is given by

J=mv-u   ...1

where, m is the mass, u is the initial velocity and v is the final velocity of the bullet.

Substitute the values of the known parameters into equation (1) to calculate the required impulse.

J=10 g×1 kg1000 g×600-0 m s-1= 6 N s

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About this question

This is a previous-year question from JEE Main 2023, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.