JEE Main 2020PhysicsCenter of Mass Momentum and CollisionMediumMCQ

JEE Main 2020 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2020 (09 Jan Shift 2)

Question

A particle of mass m is projected with a speed u from the ground at an angle θ=π3 w.r.t. horizontal (x-axis). When it has reached its maximum height, it collides completely inelastically with another particle of the same mass and velocity ui^. The horizontal distance covered by the combined mass before reaching the ground is:

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Show full solutionCorrect option: A
Correct answer
A338u2g

Step-by-step explanation


pi=pf
mu+mucosθ=2mv
⇒v=u1+cos⁡6002=34u
So horizontal range after collision =vt
=v2Hmaxg
=34u2u2sin2⁡6002g2
=34u234g=33u28g

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About this question

This is a previous-year question from JEE Main 2020, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.