JEE Main 2023PhysicsCenter of Mass Momentum and CollisionEasyMCQ

JEE Main 2023 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2023 (10 Apr Shift 1)

Question

A particle of mass m moving with velocity v collides with a stationary particle of mass 2m. After collision, they stick together and continue to move together with velocity

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Show full solutionCorrect option: A
Correct answer
Av3

Step-by-step explanation

The law of conservation of momentum is given as

m1u+m2u'=m1+m2v'

The given data is 

u=vu'=0 m s-1m1=mm2=2m

Using the conservation of momentum equation,

mv+2m(0)=(m+2m)v'⇒v'=mv3m=v3

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About this question

This is a previous-year question from JEE Main 2023, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.