JEE Main 2019PhysicsCenter of Mass Momentum and CollisionMediumMCQ

JEE Main 2019 — Center of Mass Momentum and Collision Question with Solution

JEE Main 2019 (12 Apr Shift 2)

Question

Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The x, y coordinates of the centre of mass will be:

Choose an option

Show full solutionCorrect option: A
Correct answer
A712 m, 34 m

Step-by-step explanation

Coordinates of A :0, 0
B:12 m,  32 m
C :(1 m, 0)
Coordinates of center of mass
xcm,ycm=50×0+150×12+100×150+150+100 m, 50×0+150×32+100×050+150+100 m
=712 m, 34 m

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About this question

This is a previous-year question from JEE Main 2019, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.