JEE Main 2024 — Center of Mass Momentum and Collision Question with Solution
JEE Main 2024 (06 Apr Shift 2)
Question
When kinetic energy of a body becomes 36 times of its original value, the percentage increase in the momentum of the body will be:
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Kinetic energy
If So, $\begin{aligned} \% \text { increase in momentum } & =\frac{\mathrm{P}_{\mathrm{f}}-\mathrm{P}_{\mathrm{i}}}{\mathrm{P}_{\mathrm{i}}} \times 100 \% \\ & =\frac{6 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{i}}}{\mathrm{P}_{\mathrm{i}}} \times 100 \% \\ & =500 \% \end{aligned}$
If So, $\begin{aligned} \% \text { increase in momentum } & =\frac{\mathrm{P}_{\mathrm{f}}-\mathrm{P}_{\mathrm{i}}}{\mathrm{P}_{\mathrm{i}}} \times 100 \% \\ & =\frac{6 \mathrm{P}_{\mathrm{i}}-\mathrm{P}_{\mathrm{i}}}{\mathrm{P}_{\mathrm{i}}} \times 100 \% \\ & =500 \% \end{aligned}$
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This is a previous-year question from JEE Main 2024, covering the Center of Mass Momentum and Collision chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.