JEE Main 2018 — Alternating Current Question with Solution
From: JEE Main 2018 (Offline)
Question
In an a.c. circuit, the instantaneous e.m.f. and current are given by
e = 100 sin 30 t
i = 20 sin
In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively
e = 100 sin 30 t
i = 20 sin
In one cycle of a.c., the average power consumed by the circuit and the wattless current are, respectively
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Wattless current,
here is the angle between i and e.
Average power,
Pav = Vrms Irms cos
= cos
= watt.
here is the angle between i and e.
Average power,
Pav = Vrms Irms cos
= cos
= watt.
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This is a previous-year question from JEE Main 2018, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.