JEE Main 2021 — Alternating Current Question with Solution
From: JEE Main 2021 (Online) 25th February Morning Shift
Question
A transmitting station releases waves of wavelength 960 m. A capacitor of 2.56 F is used in the resonant circuit. The self inductance of coil necessary for resonance is __________ 108 H.
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Show full solutionCorrect answer: 10
Correct answer
10
Step-by-step explanation
= 960 m
C = 2.56 F = 2.56 106 F
c = 3 108 m/s
L = ?
Now at resonance,
[Resonant frequency]
On substituting , we have
Squaring both sides :
H
C = 2.56 F = 2.56 106 F
c = 3 108 m/s
L = ?
Now at resonance,
[Resonant frequency]
On substituting , we have
Squaring both sides :
H
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