JEE Main 2019 — Alternating Current Question with Solution
From: JEE Main 2019 (Online) 8th April Evening Slot
Question
A circuit connected to an ac source of emf
e = e0sin(100t) with t in seconds, gives a phase
difference of /4 between the emf e and
current i. Which of the following circuits will
exhibit this ?
Choose an option
Show full solutionCorrect option: C
Correct answer
CRC circuit with R = 1k and C = 10 μF
Step-by-step explanation
Given phase difference = and = 100 rad/s
Reactance (X) = Resistance (R) Now by checking option.
Option (A)
R = 1000 and Xc =
Option (B)
R = 103 and XL =
Option (C)
R = 103 and Xc =
Option (D)
R = 103 and XL =
Reactance (X) = Resistance (R) Now by checking option.
Option (A)
R = 1000 and Xc =
Option (B)
R = 103 and XL =
Option (C)
R = 103 and Xc =
Option (D)
R = 103 and XL =
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This is a previous-year question from JEE Main 2019, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.