JEE Main 2020 — Alternating Current Question with Solution
From: JEE Main 2020 (Online) 9th January Evening Slot
Question
In LC circuit the inductance L = 40 mH and
capacitance C = 100 F. If a voltage
V(t) = 10sin(314t) is applied to the circuit, the
current in the circuit is given as :
capacitance C = 100 F. If a voltage
V(t) = 10sin(314t) is applied to the circuit, the
current in the circuit is given as :
Choose an option
Show full solutionCorrect option: A
Correct answer
A0.52 cos 314 t
Step-by-step explanation
Z = xC – xL
=
=
= 19.28
As Vm = ImZ
10 = Im 19.28
Im = = 0.52 A
I = 0.52 sin(314t + )
= 0.52 cos(314t)
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This is a previous-year question from JEE Main 2020, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.