JEE Main 2019 — Alternating Current Question with Solution
From: JEE Main 2019 (Online) 9th January Evening Slot
Question
A power transmission line feeds input power at 2300 V to a srep down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary of the transformer is 5A and its efficiency is 90%, the output current would be :
Choose an option
Show full solutionCorrect option: B
Correct answer
B45 A
Step-by-step explanation
Given,
Primary voltage (VP) = 2300 V
Primary current (IP) = 5A
Secondary voltage (VS) = 230 V
efficiency () = 90%
We know,
Efficiency () =
= =
0.9 =
I = 45 A
Primary voltage (VP) = 2300 V
Primary current (IP) = 5A
Secondary voltage (VS) = 230 V
efficiency () = 90%
We know,
Efficiency () =
= =
0.9 =
I = 45 A
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This is a previous-year question from JEE Main 2019, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.