JEE Main 2017PhysicsAlternating CurrentEasyMCQ

JEE Main 2017 — Alternating Current Question with Solution

JEE Main 2017 (09 Apr Online)

Question

A sinusoidal voltage of peak value 283 V and angular frequency 320 s-1 is applied to a series LCR circuit. Given that R=5 Ω, L=25 mH and C=1000 μF. The total impedance and phase difference between the voltage across the source and the current will respectively be-

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Show full solutionCorrect option: B
Correct answer
B7 Ω and 45o

Step-by-step explanation

ε0=283 volt,  ω=320 s-1

XL=320×25×10-3=8 Ω

XC=1ωC=1320×1000×10-6

XC=10000320=3.1 Ω

R=5Ω

Z= R2+XL-XC2= 50 ≈ 7Ω

tan⁡ϕ=XL-XCR=1

⟹ϕ=45o

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About this question

This is a previous-year question from JEE Main 2017, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.