JEE Main 2023PhysicsAlternating CurrentMediumNumerical

JEE Main 2023Alternating Current Question with Solution

JEE Main 2023 (01 Feb Shift 1)

Question

A series LCR circuit is connected to an ac source of 220 V, 50 Hz. The circuit contain a resistance R=100 Ω and an inductor of inductive reactance XL=79.6 Ω. The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be ______ μF.

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Show full solutionCorrect answer: 40
Correct answer
40

Step-by-step explanation

The average rate at which energy supplied i.e. power delivered is maximum in case of the resonance, therefore

XC=XL

1ωC=79.6 Ω

   C=1ω×79.6=12πf×79.6=1100π×79.6=40  μF

Hence, C=40 μF.

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About this question

This is a previous-year question from JEE Main 2023, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.