JEE Main 2013PhysicsAlternating CurrentHardMCQ

JEE Main 2013 — Alternating Current Question with Solution

JEE Main 2013 (07 Apr)

Question

The amplitude of a damped oscillator decreases to 0.9 times its original magnitude in 5s. In another 10s it will decrease to α times its original magnitude, where α equals :

Choose an option

Show full solutionCorrect option: A
Correct answer
A0.729

Step-by-step explanation

A=A0 e-bt2m

After 5 second

0.9 A 0 = A 0  e - b 5 2 m    ...... (i)

After 10 more second

A = A 0  e - b 1 5 2 m      ...... (ii)

From (i) and (ii)

A = 0.729 A 0

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Alternating Current chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2013, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.