JEE Main 2023PhysicsAlternating CurrentEasyMCQ

JEE Main 2023 — Alternating Current Question with Solution

JEE Main 2023 (25 Jan Shift 1)

Question

In an LC oscillator, if values of inductance and capacitance become twice and eight times, respectively, then the resonant frequency of oscillator becomes x times its initial resonant frequency ω0. The value of x is:

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Show full solutionCorrect option: A
Correct answer
A14

Step-by-step explanation

Resonance frequency of an LC oscillations circuit is stated as 

ω0=1LC, here, L and C represents inductance and capacitance of circuit.

Now, when inductance and capacitance changes, i.e., L'=2L and C'=8C

Then, resonant frequency is ω=12L×8C=14LC

⇒ω=ω04

Thus, the value of x=14.

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About this question

This is a previous-year question from JEE Main 2023, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.