JEE Main 2021 — Alternating Current Question with Solution
From: JEE Main 2021 (Online) 31st August Evening Shift
Question
At very high frequencies, the effective impendence of the given circuit will be ________________ .


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Show full solutionCorrect answer: 2
Correct answer
2
Step-by-step explanation
XL = 2fL
f is very large
XL is very large hence open circuit.
f is very large.
XC is very small, hence short circuit.
Final circuit

f is very large
XL is very large hence open circuit.
f is very large.
XC is very small, hence short circuit.
Final circuit

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This is a previous-year question from JEE Main 2021, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.