JEE Main 2023PhysicsAlternating CurrentMediumNumerical

JEE Main 2023 — Alternating Current Question with Solution

JEE Main 2023 (06 Apr Shift 1)

Question

An ideal transformer with purely resistive load operates at 12 kV on the primary side. It supplies electrical energy to a number of nearby houses at 120 V. The average rate of energy consumption in the houses served by the transformer is 60 kW. The value of resistive load (Rs) required in the secondary circuit will be_________mΩ.

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Show full solutionCorrect answer: 240
Correct answer
240

Step-by-step explanation

The given data is 

P=60×103 W

Vs=120 V

A transformer has a primary coil and a secondary coil.

The formula for the power delivered is given by 

P=V2sRs

⇒60×103=120×120Rs⇒Rs=120×12060×103=240 mΩ

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About this question

This is a previous-year question from JEE Main 2023, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.