JEE Main 2019PhysicsAlternating CurrentMediumMCQ

JEE Main 2019Alternating Current Question with Solution

JEE Main 2019 (10 Apr Shift 1)

Question

A transformer consisting of 300 turns in the primary and 150 turns in the secondary gives output power of  2.2 kW . If the current in the secondary coil is  10 A , then the input voltage and current in the primary coil are:

Choose an option

Show full solutionCorrect option: C
Correct answer
C440 V and 5 A

Step-by-step explanation

Assuming 100% efficiency,

V2V1=i1i2=N2N1

i1i2=N2N1i110=150300i1=5 A

P=VI2200=5×V1V1=440 V

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Alternating Current chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2019, covering the Alternating Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.