JEE Main 2019MathematicsTrigonometric Ratios & IdentitiesEasyMCQ

JEE Main 2019Trigonometric Ratios & Identities Question with Solution

JEE Main 2019 (10 Jan Shift 2)

Question

The value of cosπ22cosπ23cosπ210sinπ210 is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B1512

Step-by-step explanation

Given cosπ22·cosπ23·...·cosπ210·sinπ210

=sin29.π21029.sinπ210.sinπ210

Using  cosA.cos2A.cos22A.cos23A.cos24A.....cos2n-1A=sin2nA2nsinA

=129

=1512

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About this question

This is a previous-year question from JEE Main 2019, covering the Trigonometric Ratios & Identities chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.