JEE Main 2022MathematicsTrigonometric Ratios & IdentitiesEasyMCQ

JEE Main 2022 — Trigonometric Ratios & Identities Question with Solution

JEE Main 2022 (25 Jun Shift 2)

Question

The value of 2sin12°-sin72° is

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Show full solutionCorrect option: D
Correct answer
D31-54

Step-by-step explanation

To find ⇒2sin12°-sin72 

⇒sin12°+sin12°-sin72

⇒ sin12°+2cos42°sin-30°  ⇒sin12°-cos42°

⇒ sin12°-sin48°   ⇒2cos30°sin−18°

⇒−3sin18°=−35−14  =31−54

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About this question

This is a previous-year question from JEE Main 2022, covering the Trigonometric Ratios & Identities chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.