JEE Main 2008 — Three Dimensional Geometry Question with Solution

$\frac{x-1}{k}=\frac{y-2}{2}=\frac{z-3}{3}$ and $\frac{x-2}{3}=\frac{y-3}{k}=\frac{z-1}{2}$ Since lines intersect in a point $$\begin{array}{rl}& \left|\begin{array}{ccc}k& 2& 3\\ 3& k& 2\\ 1& 1& -2\end{array}\right|=0\\ & \therefore 2k^2+5k-25=0\\ & k=-5,5/2.\end{array}$$ Directions: Questions number 17 to 21 are Assertion-Reason type questions. Each of these questions contains two statements : Statement - 1 (Assertion) and Statement-2 (Reason). Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select the correct choice.