JEE Main 2020MathematicsThree Dimensional GeometryEasyMCQ

JEE Main 2020 — Three Dimensional Geometry Question with Solution

JEE Main 2020 (08 Jan Shift 1)

Question

The shortest distance between the lines x-33=y-8-1=z-31 and x+3-3=y+72=z-64 is

Choose an option

Show full solutionCorrect option: C
Correct answer
C330

Step-by-step explanation

w→=i^+j^–3k^
p→=3i^-j^+k^
q→=-3i^+2j^+4k^
p→×q→=ijk3-11-324=6i^-15j^+3k^
S.D.=|AB.p×q|p×q=36+225+936+225+9=330

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About this question

This is a previous-year question from JEE Main 2020, covering the Three Dimensional Geometry chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.