JEE Main 2020MathematicsThree Dimensional GeometryMediumNumerical

JEE Main 2020 — Three Dimensional Geometry Question with Solution

JEE Main 2020 (09 Jan Shift 2)

Question

If the distance between the plane, 23x-10y-2z+48=0 and the plane containing the lines x+12=y-34=z+13 and x+32=y+26=z-1λλ∈R is equal to k633, then k is equal to ____________.

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

Lines must be intersecting

⇒2s-1,4s+3,3s-1=2t-3,6t-2,λt+1
2s-1=2t-3,4s+3=6t-2,3s-1=λt+1⇒t=12,s=-12,λ=-7

Distance of plane contains given lines from given plane is same as distance between point -3,-2,1 from given plane.

Required distance equal to

-69+20-2+48529+100+4=3633=k633⇒k=3

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About this question

This is a previous-year question from JEE Main 2020, covering the Three Dimensional Geometry chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.