JEE Main 2019MathematicsThree Dimensional GeometryMediumMCQ

JEE Main 2019 — Three Dimensional Geometry Question with Solution

JEE Main 2019 (12 Jan Shift 1)

Question

The perpendicular distance from the origin to the plane containing the two lines, x + 23=y - 25=z + 57 and x - 11=y - 44=z + 47, is

Choose an option

Show full solutionCorrect option: B
Correct answer
B116

Step-by-step explanation

Direction vector of normal to the plane =i^j^k^357147=7i^-14j^+7k^

Hence, direction ratio of normal to the plane =<1, -2, 1>

Thus, equation of plane is x-2y+z+11=0

Hence, perpendicular distance from origin =1112+-22+12=116

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About this question

This is a previous-year question from JEE Main 2019, covering the Three Dimensional Geometry chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.