JEE Main 2016MathematicsStraight LinesEasyMCQ

JEE Main 2016 — Straight Lines Question with Solution

JEE Main 2016 (10 Apr Online)

Question

A straight line through origin O meets the lines 3y=10-4x and 8x+6y+5=0 at points A and B respectively. Then, O divides the segment AB in the ratio

Choose an option

Show full solutionCorrect option: C
Correct answer
C4:1

Step-by-step explanation

Let Ar1cosθ, r1sinθ

A Lies on straight line 4x+3y=10

⇒4r1cosθ+3r1sinθ=10

⇒r14cosθ+3sinθ=10
⇒r1=104cosθ+3sinθ

Let B-r2cosθ, -r2sinθ

B lies on line 8x+6y+5=0

⇒8-r2cosθ+6-r2sinθ+5=0

⇒r28cosθ+6sinθ-5=0⇒r2=58cosθ+6sinθ
∴r1r2=41

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About this question

This is a previous-year question from JEE Main 2016, covering the Straight Lines chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.