JEE Main 2020 — Statistics Question with Solution
From: JEE Main 2020 (Online) 8th January Morning Slot
Question
The mean and the standard deviation (s.d.) of
10 observations are 20 and 2 resepectively.
Each of these 10 observations is multiplied by
p and then reduced by q, where p 0 and
q 0. If the new mean and new s.d. become
half of their original values, then q is equal to
Choose an option
Show full solutionCorrect option: B
Correct answer
B-20
Step-by-step explanation
Let observations are
x1, x2, ...., x10
Here mean = 20 and standard deviation(S.D) = 2
When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|
Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q
and new mean = 20p - q and new standard deviation(S.D) = 2|p|
Given 20p - q = = 10
and 2|p| = = 1
p =
If p = then q = 0 (not possible as given q 0)
If p = - then q = -20
Here mean = 20 and standard deviation(S.D) = 2
When each of these 10 observations is multiplied by p then new observations are px1, px2, ....., px10
and new mean = 20p and new standard deviation(S.D) = 2|p|
Now when Reduced by q then new observations are
px1 - q, px2 - q, ....., px10 - q
and new mean = 20p - q and new standard deviation(S.D) = 2|p|
Given 20p - q = = 10
and 2|p| = = 1
p =
If p = then q = 0 (not possible as given q 0)
If p = - then q = -20
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