JEE Main 2020 — Statistics Question with Solution
From: JEE Main 2020 (Online) 3rd September Morning Slot
Question
For the frequency distribution :
Variate (x) : x1 x2 x3 .... x15
Frequency (f) : f1 f2 f3 ...... f15
where 0 < x1 < x2 < x3 < ... < x15 = 10 and
> 0, the standard deviation cannot be :
Variate (x) : x1 x2 x3 .... x15
Frequency (f) : f1 f2 f3 ...... f15
where 0 < x1 < x2 < x3 < ... < x15 = 10 and
> 0, the standard deviation cannot be :
Choose an option
Show full solutionCorrect option: A
Correct answer
A6
Step-by-step explanation
If variate varries from m to M then variance
(M = upper bound of value of any random variable,
m = Lower bound of value of any random variable)
Here M = 10 and m = 0
6
(M = upper bound of value of any random variable,
m = Lower bound of value of any random variable)
Here M = 10 and m = 0
6
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