JEE Main 2017MathematicsStatisticsEasyMCQ

JEE Main 2017Statistics Question with Solution

JEE Main 2017 (02 Apr)

Question

A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A125

Step-by-step explanation

For Bernoulli's trials

Variance =n.p.q

Given, number of trials n=10

Probability of drawing a green ball p=1525=35 and q=25

Hence, Variance =10×35×25=125

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Statistics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2017, covering the Statistics chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.