JEE Main 2019 — Sets And Relations Question with Solution
From: JEE Main 2019 (Online) 9th April Evening Slot
Question
Choose an option
Show full solutionCorrect option: D
Step-by-step explanation

The total population to be 100 (for simplicity's sake) and the percentages can be treated as actual numbers of people in this context.
The percentage of people who read newspaper A is given as 25. However, among these, there are people who read both newspapers A and B, given as 8. To find the number of people who read only newspaper A, we subtract the number of people who read both from the total number of people who read A. That is,
n(A only) = 25 – 8 = 17
Similarly, the number of people who read only newspaper B is calculated as :
n(B only) = 20 – 8 = 12
Now, we are given the percentage of each of these groups that look into the advertisements:
- 30% of those who read A but not B,
- 40% of those who read B but not A,
- 50% of those who read both A and B.
To find the total percentage of the population that looks into advertisements, we add up the contributions from each of these groups. We calculate each group's contribution by multiplying the size of the group by the percentage of that group that looks at advertisements :
= (from A only) + (from B only) + (from both A and B)
= 5.1 (from A only) + 4.8 (from B only) + 4 (from both A and B)
Adding these up, we get
= 13.9
This means that 13.9% of the total population looks into the advertisements.
So, the correct answer is :
Option D : 13.9.
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This is a previous-year question from JEE Main 2019, covering the Sets And Relations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.