JEE Main 2016MathematicsSequences And SeriesArithmetic ProgressioneasyMCQ

JEE Main 2016Sequences And Series Question with Solution

From: JEE Main 2016 (Online) 10th April Morning Slot

Question

Let a1, a2, a3, . . . . . . . , an, . . . . . be in A.P.

If a3 + a7 + a11 + a15 = 72,

then the sum of its first 17 terms is equal to :

Choose an option

Show full solutionCorrect option: A
Correct answer
A306

Step-by-step explanation

As  a1 a2 . . . . . an . . . . . are in A.P.

   a3 + a15 = a7 + a11 = a1 + a17

Given,

a3 + a7 + a11 + a15 + a15 = 72

   (a3 + a15) + (a7 + a11) = 72

   2(a1 + a17) = 72

   (a1 + a17) = 36

   Sum of first 17 terms

= (a1 + a17)

= 36

= 306

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About this question

This is a previous-year question from JEE Main 2016, covering the Sequences And Series chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.