JEE Main 2019MathematicsQuadratic EquationMediumMCQ

JEE Main 2019 — Quadratic Equation Question with Solution

JEE Main 2019 (09 Jan Shift 2)

Question

If both the roots of the quadratic equation x2-mx+4=0 are real and distinct and they lie in the interval 1, 5, then m lies in the interval:

Note: In the actual JEE paper interval was 1, 5

Choose an option

Show full solutionCorrect option: D
Correct answer
D4, 5

Step-by-step explanation

Given roots of x2-mx+4=0 are distinct and lies in 1, 5, Following conditions must be true

(i) D>0⇒m2-16>0

⇒m-4m+4>0

⇒m∈-∞, -4∪4, ∞

(ii) f1>0⇒m<5

(iii) f5>0⇒m<295 

(iv) 1<-b2a<5⇒2<m<10

Taking intersection of all conditions, we get m∈4, 5

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About this question

This is a previous-year question from JEE Main 2019, covering the Quadratic Equation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.