JEE Main 2019 — Probability Question with Solution
From: JEE Main 2019 (Online) 9th January Morning Slot
Question
Two cards are drawn successively with replacement from a well-shuffled deck of 52 cards. Let X denote the random variable of number of aces obtained in the two drawn cards. Then P(X = 1) + P (X = 2) equals :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
P (X = 1) means out of two drawn cards one card is ace.
and P(X = 2) means both the drawn cards are ace.
P(X = 1) = first card is ace or 2nd card is ace.
= A _ _ A
=
=
P(X = 2) = First and second both cards arc ace.
= A A
=
P(X = 1) + P(X = 2)
=
=
and P(X = 2) means both the drawn cards are ace.
P(X = 1) = first card is ace or 2nd card is ace.
= A _ _ A
=
=
P(X = 2) = First and second both cards arc ace.
= A A
=
P(X = 1) + P(X = 2)
=
=
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This is a previous-year question from JEE Main 2019, covering the Probability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.