JEE Main 2022MathematicsProbabilityMediumMCQ

JEE Main 2022 — Probability Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

A random variable X has the following probability distribution:

X 0 1 2 3 4
PX k 2k 4k 6k 8k

The value of P1<x<4x≤2is equal to

Choose an option

Show full solutionCorrect option: A
Correct answer
A47

Step-by-step explanation

To find P1<x<4x≤2 or PAB

We know that

 PAB=PA∩BPB

Given

x 0 1 2 3 4
Px k 2k 4k 6k 8k

PA=2,3

PB=0,1,2

PA∩B=Px=2

PB=Px=0+Px=1+Px=2

So   PAB=Px=2Px=0+Px=1+Px=2

=4kk+2k+4k=4k7k=47

Hence option A is correct.

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About this question

This is a previous-year question from JEE Main 2022, covering the Probability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.