JEE Main 2021MathematicsProbabilityMediumMCQ

JEE Main 2021 — Probability Question with Solution

JEE Main 2021 (25 Feb Shift 2)

Question

In a group of 400 people, 160 are smokers and non-vegetarian; 100 are smokers and vegetarian and the remaining 140 are non-smokers and vegetarian. Their chances of getting a particular chest disorder are 35%,20% and 10% respectively. A person is chosen from the group at random and is found to be suffering from the chest disorder. The probability that the selected person is a smoker and non-vegetarian is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D2845

Step-by-step explanation

Consider following events
A : Person chosen is a smoker and non
vegetarian.

B : Person chosen is a smoker and vegetarian.

C : Person chosen is a non-smoker and vegetarian

E : Person chosen has a chest disorder

Given

PA=160400PB=100400PC=140400

PEA=35100PEB=20100PEC=10100

To find

PAE=PAPEAPA·PEA+PB·PEB+PC·PEC

=160400×35100160400×35100+100400×20100+140400×10100

=2845

option 4

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About this question

This is a previous-year question from JEE Main 2021, covering the Probability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.