JEE Main 2019 — Parabola Question with Solution
From: JEE Main 2019 (Online) 11th January Evening Slot
Question
If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4(x – a2) = 0 and the othertwo vertices are the points of intersection of the parabola and y-axis, is 250 sq. units, then a value of 'a' is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D5
Step-by-step explanation
Vertex is (a2, 0)
y2 (x a2) and x 0 (0, 2a)
Area of triangle is 4a.(a2) = 250
a3 = 125 or a = 5
y2 (x a2) and x 0 (0, 2a)
Area of triangle is 4a.(a2) = 250
a3 = 125 or a = 5
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