JEE Main 2017 — Parabola Question with Solution
From: JEE Main 2017 (Online) 9th April Morning Slot
Question
If y = mx + c is the normal at a point on the parabola y2 = 8x whose focal distance is 8 units, then is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
c = 29m 9m3
a = 2
Given (at2 a)2 + 4a2t2 = 64
(a(t2 + 1)) = 8
t2 + 1 = 4 t2 = 3
t =
c = 2at(2 + t2)
=
= 10
a = 2
Given (at2 a)2 + 4a2t2 = 64
(a(t2 + 1)) = 8
t2 + 1 = 4 t2 = 3
t =
c = 2at(2 + t2)
=
= 10
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This is a previous-year question from JEE Main 2017, covering the Parabola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.