JEE Main 2020 — Parabola Question with Solution
From: JEE Main 2020 (Online) 3rd September Morning Slot
Question
Let P be a point on the parabola, y2
= 12x and
N be the foot of the perpendicular drawn from
P on the axis of the parabola. A line is now
drawn through the mid-point M of PN, parallel
to its axis which meets the parabola at Q. If the
y-intercept of the line NQ is ,
then :
Choose an option
Show full solutionCorrect option: D
Correct answer
DMQ =
Step-by-step explanation
Let P = (3t2 , 6t) ; N = (3t2 , 0)
M = (3t2 , 3t)
Let point Q = (h, 3t) which lies on the parabola y2 = 12x
9t2 = 12h
h =
Equation of NQ
y - 0 =
y =
For y-intercept of NQ, x = 0
y = 4t
Given y-intercept of the line NQ is
4t =
t =
MQ = =
PN = 6t = 2
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This is a previous-year question from JEE Main 2020, covering the Parabola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.