JEE Main 2021 — Parabola Question with Solution
From: JEE Main 2021 (Online) 20th July Morning Shift
Question
Let the tangent to the parabola S : y2 = 2x at the point P(2, 2) meet the x-axis at Q and normal at it meet the parabola S at the point R. Then the area (in sq. units) of the triangle PQR is equal to :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Tangent at P : y(2) = 2(1/2) (x + 2)
2y = x + 2
Q = (2, 0)
Normal at P : y 2 =
y 2 = 2(x 2)
y = 6 2x
Solving with y2 = 2x R
Ar (PQR) = {1 \over 2}\left| {\matrix{ 2 & 2 & 1 \cr { - 2} & 1 & 1 \cr {{9 \over 2}} & 3 & { - 1} \cr } } \right|
sq. units.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Parabola chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Parabola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.