JEE Main 2019MathematicsInverse Trigonometric FunctionsMediumMCQ

JEE Main 2019Inverse Trigonometric Functions Question with Solution

JEE Main 2019 (12 Jan Shift 1)

Question

Considering only the principal values of inverse functions, the set A=x0 : tan-12x+tan-13x=π4

Choose an option

Show full solutionCorrect option: D
Correct answer
DIs a singleton

Step-by-step explanation

Given tan-12x+tan-13x=π4

tan-12x+3x1-2x×3x=π4

Applying tangent on both sides,

5x1-6x2=1 tanπ4=1

5x=1-6x2

6x2+5x-1=0

6x2+6x-x-1=0

6x-1x+1=0

x=-1, 16

But, since x0.

Hence, x=16

 A has only one element and thus, it is a singleton.

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About this question

This is a previous-year question from JEE Main 2019, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.