JEE Main 2024MathematicsInverse Trigonometric FunctionsEasyMCQ

JEE Main 2024 — Inverse Trigonometric Functions Question with Solution

JEE Main 2024 (31 Jan Shift 2)

Question

If a=sin−1sin5 and b=cos−1cos5, then a2+b2 is equal to

Choose an option

Show full solutionCorrect option: B
Correct answer
B8π2−40π+50

Step-by-step explanation

Given: a=sin-1sin5 and b=cos-1cos5

⇒a=5-2π and b=2π-5

⇒a2+b2=5-2π2+2π-52

⇒a2+b2=25+4π2-20π+4π2+25-20π

⇒a2+b2=8π2-40π+50

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About this question

This is a previous-year question from JEE Main 2024, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.